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[quote uid=merrylarry pid=1116] 7a)titan/360×2pie r cos t d=55/360×2×22/7×640 cos 4 d=55×44×6400 cos 4/2520 d=55×44×6400×0496/2520 d=15,449.28/2520 d=6130.67 d~6130km. ii)distance along gent circle D=tita/360×2pie r D=55/360×2/7×22/7×6400/1 D=55×44×6400/2520 D=15,488×6400/2520 D=6144.03 D=~6146km. 7b) Length of sector tita/360×2pie r L=120/360×2/1×22/7×42/1 L=120×44×42/2520 L=221760/2520 L=88cm L=2pie r Where r is the radius of circumference 88=2×22/7×r 88×7=44r R=88×7/44 R=616/44 R=14cm. Curved surface area = pie rc A=22/7×14×42/1 A=22×14×4^2/7 A=12936/7 A=1848cm^2. 8a) X=60/t ———->(i) Y=180/t ———->(ii) T1=60/X T2=100/Y T1+T2=5 60/X+180/Y = 300 ———->(i) 180/X + 60/Y = 260 ———->(ii) Let P =1/X 2 = 1/Y 60p + 180 Q = 300 180p + 6Q = 200 P + 3Q =5 9P + 3Q =13 Substract (i)from (ii) 8p = 8 P = 8/8 ÷ P = 1 Subtract P into (i) P + 3Q =5 1 + 3Q =5 3Q =5-1 3Q =4 Q = 4/3 P = 1 ÷ 1 = 1/X ÷ X = 1 4/3 = 1/Y ÷ Y = 3/4 8b) 2001 ——— 25,700 2002 ——— 15/100 X 25,700 + 25,700 = 29,555 Amount of tax in 2002 = 29,555 * 12.5/100 = N3694.375 =N3690 8c) Log25 Log16 25/100 Log16 2/4 Log4 6-1 -1/2 Log4^4 -1/2 =========================== 9ai) W=K+C/2 24 = k+ C/16 384 = 16K + C ——-(i) 18 = K + C/4 72 + 4K + C ———(ii) 16K + C = 384 4K + C = 72 Substact (ii) from (i) 12k/12 = 312/12 K = 26 Substract K into (i) 16k + C = 384 C = 384 – 416 C = -32 W=k+C/t2 W=26-32/t2 (ii) When W= -46,t=? -46 = 26 -32/t2 t2 = -32/-72 t = Sqrt 16/36 = 4/6 =2/3 9b) V = Pie r2 . d = 14,r = 7cm 1232 = 22/7 * 7^2 * h h = 7*1232/22*49 h = 8624/1074 h = 8cm =========================== 11a) y^1=x^2(3x+1)^2 v=(2x+1)^2 v=m^2 dm/dx=2 dv/dm=2m dy/dx=dv/dm×dm/dx =2m×2 =4m dy/dx=4(2x+1) dy/dx=udv/dx+v whole no. dy/dx =x^2 4(xx+1)^2,×3x =4x^2(2x+1)+2x(2x+1)^2. 11b) [3 3-1] [1 0 2] [3 – 2 3] +2[0-(-4)-3[63] +-1(-2) 8+9+2 =19. 11c) m=y2-y1/x2-x1 y-y1= m(x-x2) m=4-3/-1-2 m=-1/3 y1-y2=-1/3(x-x2) y-3=1/3(x-2) y-3=-4/3+2/3 3y=-x+11 y=-1/3x+11/3 [/quote]